x^2-4x-1085=0

Solution for x^2-4x-1085=0 equation:

x^2-4x-1085=0

a = 1; b = -4; c = -1085;
Δ = b2-4ac
Δ = -42-4·1·(-1085)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-66}{2*1}=\frac{-62}{2}
=-31
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+66}{2*1}=\frac{70}{2}
=35
$